Hello. Question.
This motherboard will be good?
ASUS PRIME Z390-P - Sklep komputerowy - x-kom.pl
I want buy with 2080 ti and 9900k. No issues? I dont want to overprize or something.
Somebody said:"
I wouldn't do that either.
As efficiency will go down, and power consumption will go to the roof, especially on that i9-9900K.
Btw, a test of a bunch of the cheapest Z390 chip-set boards in comparison.
Are Budget Z390 Motherboards a Scam? VRM Thermal Test - YouTube
Actually, some people make it the wrong way.
They buying the fastest CPU and the most expensive CPU cooler, without even considering the factor motherboard.
The smartest way would be, to lower your expectations on a CPU and CPU cooler, and invest more on a proper board.
And if you want an i9-9900K, you shouldn't cheap out on the board, as the core voltage raises depending the workloads of the processor.
If you get an voltage of 1.28 on that budget Asus board medium workload if you push the processor hard, the V-core will raise, the VRMs will not keep up and the CPU cooler will not save the day either.
The V-core will drop for not damaging the system, and the i9-9900K will go down with the core speeds. (aka throttle)
You could get a cheaper CPU cooler for keeping the processor at reasonable temps, but for getting the boost clocks working at full throttle on that i9-9900K you definitely need a good board for keeping a low and steady V-core.
Otherwise, boost clocks will go down to ~4.2GHz on that processor on all cores. (that's with an non OCed i9-9900K)
If you try to OC though, your system will either throttle severely or even crash!
And that's a shame, because with the proper system configuration the i9-9900K would run with high boost clocks and that obsoletes an manual overclock as well.
That processor is a beast, and if someone makes it right, the i9-9900K will run between 4.7-5.0 GHz (depending the work load of the cores) right out of the Box."
Sorry but i dont understand this guy. Performance will be lower on this mobo for what?!
So maybe Prime z390-A ? But is expensive
This motherboard will be good?
ASUS PRIME Z390-P - Sklep komputerowy - x-kom.pl
I want buy with 2080 ti and 9900k. No issues? I dont want to overprize or something.
Somebody said:"
I wouldn't do that either.
As efficiency will go down, and power consumption will go to the roof, especially on that i9-9900K.
Btw, a test of a bunch of the cheapest Z390 chip-set boards in comparison.
Are Budget Z390 Motherboards a Scam? VRM Thermal Test - YouTube
Actually, some people make it the wrong way.
They buying the fastest CPU and the most expensive CPU cooler, without even considering the factor motherboard.
The smartest way would be, to lower your expectations on a CPU and CPU cooler, and invest more on a proper board.
And if you want an i9-9900K, you shouldn't cheap out on the board, as the core voltage raises depending the workloads of the processor.
If you get an voltage of 1.28 on that budget Asus board medium workload if you push the processor hard, the V-core will raise, the VRMs will not keep up and the CPU cooler will not save the day either.
The V-core will drop for not damaging the system, and the i9-9900K will go down with the core speeds. (aka throttle)
You could get a cheaper CPU cooler for keeping the processor at reasonable temps, but for getting the boost clocks working at full throttle on that i9-9900K you definitely need a good board for keeping a low and steady V-core.
Otherwise, boost clocks will go down to ~4.2GHz on that processor on all cores. (that's with an non OCed i9-9900K)
If you try to OC though, your system will either throttle severely or even crash!
And that's a shame, because with the proper system configuration the i9-9900K would run with high boost clocks and that obsoletes an manual overclock as well.
That processor is a beast, and if someone makes it right, the i9-9900K will run between 4.7-5.0 GHz (depending the work load of the cores) right out of the Box."
Sorry but i dont understand this guy. Performance will be lower on this mobo for what?!
So maybe Prime z390-A ? But is expensive
