@Stratotanker
Hier ein paar Infos:
Download this document and see page 19.
http://developer.intel.com/design/pentiumiii/datashts/244452.htm
The VID pins are (A119, A120, A121, B119, B120).
B120 is VID0
A120 is VID1
A119 is VID2
B119 is VID3
A121 is VID4
Vcore, VID4, VID3, VID2, VID1, VID0
1.65v, 0, 1, 0, 0, 0
1.70v, 0, 0, 1, 1, 1
1.75v, 0, 0, 1, 1, 0
1.80v, 0, 0, 1, 0, 1
1.85v, 0, 0, 1, 0, 0
1.90v, 0, 0, 0, 1, 1
"0= processor pin connected to Vss"
"1=open on processor"
So, a zero means that pin is connected to Vss in the chip and a 1 means that pin is not connected to Vss. If you have a pin that is already connected to Vss at the default voltage for that particulr processor then covering it with tape will break the connection and change it from 0 to 1. If you have a pin that is open or 1 at the default voltage for the particulr processor then in order to change it to 0 you will need to connect it to Vss or another pin which is already connected to Vss and is already 0.
1.65v -> 1.75v
Vcore......VID4......VID3.....VID2.....VID1....VID0
1.65v...........0..........1...........0.........0.........0
1.75v...........0..........0...........1.........1.........0
Okay, since 0 is connected to Vss or ground the pins that are 0 are already connected to Vss inside the chip and the pins that are 1 are simply left open. So, to go from 1.65v to 1.75v we need to change VID2 and VID1 from 0 to 1. The way we would do this is somehow break the connection by doing something like covering the pins with tape or painting them with fingernail polish or some other insulator to break the connection to Vss and therefore change these pins from 0 to 1. Doing this will give us 0,1,1,1,0, which according to the table in that document would give us 1.35v. Now in order to get 1.75v we would also need to change VID3 from 1 to 0 thus giving us 0,0,1,1,0 which in the table corresponds to 1.75v. Now since VID3 is 1 to begin with that means it is simply left open and does not connect to anything inside the CPU. To make it 0 we must connect it to Vss. The easiest way to do this would be to connect to a pin which is already 0 or already connected to Vss. What we could do is connect it to VID4 (or VID0). Since VID4 is 0 and already connected to Vss inside the CPU, then connecting VID3 to VID4 would be connecting it to Vss and thus make it 0 also. This should give us 1.75V.
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Also sieht so aus als musst Du die Pins A119 und A120 abkleben - und Pin B119 mit B120 verbinden.
Alternativ geht das auch mit den Widerständen umlöten:
http://www.geocities.co.jp/SiliconValley-Oakland/1225/data-image/secc2-core.gif
Hier siehst Du auch wo die Pins jeweils sind.